Left Handed Maxwell SystemsPART-7Magneto-Inductive Waves SAMEER Shantanu DasRR&PSReactor Control Division, B.A.R.C. Mumbai-400085shantanu@barc.gov.in
Magneto Inductive (MI) wavesAlong with ‘backward waves’ the Magneto-Inductive (MI) waves are becoming popular in this particular field
This happens or forms when two loops of SRR close to each other are ‘coupled’ to one another due to
magnetic field of one loop ‘threading’ the other SRR. These coupling leads to waves are called MI waves
ω
The dispersion equation is: ,
0
ω =
is resonant frequency
ω
of SRR,
L is
0
inductance, the mutual
2
MM1 +
co s(
ka )
inductance
Ln + 1
nn + 1
n − 1
nn − 1
Axial coupling
M > 0 Planer coupling
M < 0
For positive
M the central ring’s voltage drop due to its own current
Z I0
nwill try to increase due to the induced voltage due to adjacent rings
jω and
M Ijω
M In −1
n +1
Thus we write KVL for SRR-
n as:
Z I +
jω
M I+
jω
M I= 0
0
nn −1
n +1
−1
[
R +
jω
L + (
jω
C )
]
I= −
jω
M (
I+
I)
nn −1
n +1
Magneto Inductive (MI) waves positive and negative mutual inductancesMutual impedance between two elements is defined as ratio of the voltages in element-2 to the current in
element-1, that introduced it. Corresponding vector potential is
A = ( μ / 4π
(
J /
r )
d v∫
0
)
and the magnetic field is
H fitted
= ∇ ×
Aover the area of loop-2. The flux threading the two loop-2
with mutual inductance
M is . Note the is ‘com
M 21
plex quantity’ if the distance
φ =
2 1
MI2
2 1 1
between elements becomes comparable to wave-length.
Mutual inductance is positive if magnetic lines cross the two loops in the same direction, and negative if the
magnetic lines are in opposite direction
I1
Ilo o p − 1
1
lo o p − 1
lo o p - 2
lo o p - 2
Axial coupling
M > 0 Planer coupling
M < 0
The MI waves considered here are threaded to SRR which does not form a very long line so that
retardation effect and its losses due to radiation are not considered presently. So the MI lines are ‘short’.
The Dispersion expressionFrom the KVL of the
n-th SRR we have
Z I +
jω
M I+
jω
M I= 0
0
nn −1
n +1
−1
[
R +
jω
L + (
jω
C )
]
I= −
jω
M (
I+
I)
nn −1
n +1
−
jknaI=
I ew ave - so lu tio n assu m ed an d su b stitu te
n0
⎛
1
⎞
R +
+
jω
L I = −
jω
M (
I+
I)
⎜
⎟
nn −1
n +1
⎝
jω
C⎠
2
2
jω
R C + 1 +
j ω
L C−
jkna−
jk (
n −1)
a−
jk (
n +1)
I e= −
jω
M I (
ae+
e)
0
0
jω
C2
2
2
jk a−
jka2
jω
R C + 1 − ω
L C = −
j ω
M C (
e+
e) = ω 2
M C co s(
ka )
T ak e
R as zero lo ssle
2
ss; an d reso n an t freq u en cy o f S R R as ω
= (1 /
L C )
0
2
2
ω
ω 2
M1 −
−
co s
ka = 0
2
2
ω
ω
L0
0
2
ω ⎛
2
M⎞
1 +
co s
ka= 1
T h is is d isp ersio n relatio n
⎜
⎟
2
ω ⎝
L⎠
0
Dispersion R not equal to zero a lossy case with k as complex number (with attenuation)From previous expansion of KVL for the
n-th SRR with loss resistance
R we have
2
2
2
jk a−
jka2
jω
R C + 1 − ω
L C = −
j ω
M C (
e+
e) = ω 2
M C c o s (
k a )
2
2
2
jω
R L Cω
ω
2
Mω
L+ 1 −
−
κ cos
ka = 0
κ =
p u t
Q =
2
2
ω
Lω
ω
LR0
0
2
2
2
ω 1
ω
ω
j+ 1 −
−
κ cos( β
a −
jα
a ) = 0
w h e re
k = β −
jα
2
2
2
ω
Qω
ω
0
0
0
2
2
2
ω 1
ω
ω
j+ 1 −
−
κ (cos β
a cos
jα
a + sin β
a sin
jα
a ) = 0
2
2
2
ω
Qω
ω
0
0
0
w ith
c o s
jx = c o sh
xsin
jx =
j sin h
x2
2
ω 1
ω
2
2
ω
ω
j+ 1 −
−
κ cos β
a cosh α
a −
jκ sin β
a sinh α
a = 0
2
2
ω
Qω
2
2
ω
ω
0
0
0
0
s e g re g a tin g re a l & im a g in a ry p a rts , a n d e q u a tin g to z e ro
2
2
ω
ω
1 −
−
κ cos β
a cosh α
a = 0
2
2
ω
ω
0
0
1 − κ sin β
a sinh α
a = 0
Q
Circuit couplingMMMLLLLCCCCVn−2
RRVRVn −1
nVn+1
Rt h
ZI+
j ω
M(
I+
I) =
0
K V L f o r
n l o o p
0
nn − 1
n + 1
1
Z=
j ω
L+
+
Rs e l f i m p e d a n c e
0
j ω
Cjk n aAssume wave solution in form:
I I e −
=
= β − α
n0
where
k jcomplex quantity with
β as propagation constant,
α as attenuation. The dispersion relation
1
− 2
⎛
2
Mω
ω
⎞
=
1 +
co s
ka2
0 ⎜
⎟
⎝
ω
L⎠
1 −
[1 + κ co s( β
a ) co sh (α
a )] = 0
may be separated into real and imaginary parts yielding
2
ω 0
1 − κ sin(β
a) sinh(α
a) = 0
Qκ = 2
M /
Lco u p lin g co efficien t
Q = ω
L /
Rlo sses
Planer and Axial coupling of SRR with excitation and termination to form ‘backward’and ‘forward’ MI wavesyaN1
2
3
4
xzNV4
1
Z t3
2
Z1
tr0
yaxzV 1
Small losses dispersion expression2
ω
1 −
[1 + κ co s( β
a ) co sh (α
a )] = 0
2
ω 0
an d
1 − κ sin(β
a) sinh(α
a) = 0
Qα ≅ 0
co sh α
a = 1
p u ttin g ab o ve
2
ω
1 −
[1 + κ co s( β
a )] = 0
2
ω 0
ω = ω / 1 + κ cos(β
a )
is lo ss - less d isp ersio n !
0
If the losses are small then and thus attenuation thus
α ≅ 0
c o s h ( α
a ) ≅ and
1
s i n h ( α
a ) ≅ α
awhich means in the dispersion equation for phase change per element remains same, and losses
per element given as:
1
α
a = κ
Q s i n ( β α )
It may be expected that losses decline as the coupling coefficient a
κ
nd increases
Q
Waves on four poleSimilar to part-2 where explanation of dispersion given through TL circuit approach
IIinoutZVVYoutinV=
I Z +
Vi ni no u tI−
Ii no u tV=
o u tY⎡
V⎤
⎡
bb⎤ ⎡
V ⎤
o u t1 1
1 2
in=
⎢
⎥
⎢
⎥ ⎢
⎥
IbbI⎣
out ⎦
⎣ 21
2 2 ⎦ ⎣
in ⎦
b= 1
b= −
Zb= −
Yb= 1 +
YZ1 1
1 2
2 1
2 2
G e n e ra l d is p e rs io n e q u a tio n
2 c o s
k a =
b+
b1 1
2 2
Coupled SRR circuit and dispersionIIino u tLCVMVi no u t⎡
0
−
jω
M⎤
⎢
⎥
M> 0
2
B =
ω
1
L ⎛
ω ⎞
⎢
ω
0
0
⎥
−
−
⎜ 1 −
⎟
− κ
2
⎢
1
jω
MMω
⎥
⎣
⎝
⎠ ⎦
ω 0
M< 0
2
LL ω
ω
0
2 c o s
k a =
b+
b= −
+
0
1 1
2 2
2
MMω
1 + κ
ω 0
ω =
κ = 2
M /
L0
π
π
1 + κ c o s (
k a )
k a2
Dispersion lossless case
α = 0
Q = ∞
κ = ± 0 . 1
Backward wave for
M < 0
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