Relativity Theory is Dead

Relativity Theory is Dead
By Professor Joe Nahhas, 1977
joenahhas1958@yahoo.com

Abstract: The elimination of relativity theory is a matter of time and not a matter of
science. The problem in all of physics is wrong experimental data and measurements.
Correcting data and measurements mistakes of past 150 years will cure physics from 20th
century wrong physics. 20th century wrong physics starts with relativity theory. Taking
all of relativity theory experimental proofs and proves that it amounts to nothing and a
case of 109 years of Nobel Prize winner physicists and 400 Years of Astronomy that can
not read a telescope is not going to end relativity. Physicists built 150 years of physics on
wrong concepts of relativity. Physics progress requires the death of relativity theory and
100,000 living physicists relativistic education attached to it. All relativity theory
experimental is visual effects and the proofs are below and I challenge all to prove me
wrong.

This Article is Relativity Theory Death Certificate.

A- General relativity has 5 textbook and college taught experimental proofs
1- Mercury's Perihelion of 43 arc sec per century -----------------------------------------I
2- GPS 45 micro second per century -------------------------------------------------------II
3- Planetary Telecommunications time delays (Shapiro) 250 micro second round trip - III
4- Pound Rebka Harvard University Davis Lab experiments ------------------------ IV
5- Lord Eddington's Light Bending Experiment. --------------------------------------- V
B- Special relativity is based on two erroneous principles
6- Length contraction -------------------------------------------------------------------- VI
7- Constant velocity of light ------------------------------------------------------------ VII
That produced wrong physics of
8- Time Dilations ------------------------------------------------------------------------ VIII
9- E = mc² -------------------------------------------------------------------------------- IX
10- Nuclear dark energy ---------------------------------------------------------------- X

Relativity theory Death Certificate

1- Real time Physics: We can only measure past events. We can not measure something
that did not happen. We can only measure things that had happened. What we measure in
not what happened. We measure in present time an event that happened in past time.
Present time = present time
Present time = past time + [present time - past time]
Present time = past time + real time delays
Real time physics = event time physics + real time relativistic delays

---

What one sees is relativistic = what happened in an absolute event + relativistic effects
What happened in an event is absolute = real time physics - real time relativistic effects.
Observer time = observed time + time delays
Real time = absolute time + time delays
Real time = Event time + time delays
Real time Physics = event time Physics + time delays Physics
2 - Real time Universe

All there is in the Universe is objects of mass m moving in space (x, y, z) at a location
r = r (x, y, z). The state of any object in the Universe can be expressed as the product.

S = m r; State = mass x location:

A - Real time location
[λ (r)] t
An object at of absolute location r when measured in real time a decay factor of ℮
[ ω (r)] t
[λ (r) + ω (r)] t
and a motion factor of ℮
is introduced to a total factor of ℮

and the
[λ (r) + ω (r)] t
location of an object measured in real time is r = r (0) ℮



B - Real time mass
[λ (m)] t
An object at of absolute mass m when measured in real time a decay factor of ℮
[ ω (m)] t
[λ (r) + ω (r)] t
and a motion factor of ℮
is introduced to a total factor of ℮

and
[λ (m) + ω (m)] t
the location of an object measured in real time is m = m (0) ℮



3 - Real time location along the line of measurement and perpendicular to the line of
measurement.
[λ (r) + ω (r)] t
[λ (r)] t
ω (r) t
S = r ℮

= r ℮
℮
[λ (r)] t

S x + S y = r ℮
[cosine ω t + sine ω t]
Along the line of measurement
[λ (r)] t
S x = r ℮
cosine ω t
[λ (r)] t
S x = r ℮
√ [1 - sine² ω t]
Perpendicular to line of measurements
[λ (r)] t
S y = r ℮
sine ω t
Taking ω T = arc tan (v/c)
Along the line of measurement
[λ (r)] t
Then S x = r ℮
√ [1 - sine² arc tan (v/c)]
Perpendicular to line of measurements
[λ (r)] t
And S y = r ℮
sine arc tan (v/c)

4 - Real time location motion visual effects along the line of measurement
[λ (r)] t
S x = r ℮
√ [1 - sine² arc tan (v/c)]
With λ (r) = 0
Then

---

S x = r √ [1 - sine² arc tan (v/c)]
5 - Lorentz's length contraction historical mistake.
S x = r √ [1 - sine² arc tan (v/c)]
With (v/c) << 1
Then S x = r √ [1 - (v/c) ²]
This is Lorentz's length contraction 150 years historical mistake -------------- VI

5 - Einstein's constant velocity of light historical mistake
S x = r √ [1 - (v/c) ²]
S x = c Γ and r = c t ------------------------------------------------------------------VII
Then c Γ = c t √ [1 - (v/c) ²]
And Γ = t √ [1 - (v/c) ²]

6 - Einstein's special relativity theory time dilation historical mistake
Γ = t √ [1 - (v/c) ²] ------------------------------------------------------------------ VIII

7 - Time Factor

S x = r √ [1 - sine² arc tan (v/c)]
S x = r √ [1 - sine² arc tan (v/c)]
If (v/c) = (1/n) = (1/ refractive index) and the velocity is constant in absolute value
Or S x = c Γ (x) and r = c t; then
Γ (x) = t √ [1 - sine² arc tan (v/c)]
Along the line of measurement
Γ (x) = t √ [1 - sine² arc tan (1/n)]
Perpendicular to the line of measurement
S y = r sine arc tan (v/c)
S y = r sine arc tan (v/c)
And Γ (y) = t sine arc tan (v/c) = t sine arc tan (1/n)

8- Reins and Cowan 1953 Savannah River Neutrino experiment historical dark
energy mistake.
Along the line of measurement
Γ (x) = t √ [1 - sine² arc tan (1/n)]
With t = 25 µ s
And n of water = 1.33 < n < 1.44 = n of tri ethyl benzene
Γ (x) = t √ [1 - sine² arc tan (1/n)]
4.67 µ s < Γ (x) < 5 µ s -------------------------------------------------------------------- X

9 - Real time Straight line
[λ (r) + ω (r)] t
S = r ℮


With λ (r) = 0 [ ω (r)] t

Then S = r ℮
= r [cosine ω t + sine ω t]
Let r = r î = v t î

Then S = v t î [cosine ω t + sine ω t]

S x + S y = v t î [cosine ω t] + v t î [ sine ω t]

---

Along the line of measurement
S x = v t cosine ω t

S y = v t sine ω t

At time of measurement w T = arc tan (v/c)
S x = v t cosine arc tan (v/c)

S y = v t sine arc tan (v/c)
If v = c
Then S x = v t cosine arc tan (v/c) = c t cosine arc tan (c/c) = c t cosine (π/4) = c t /√ 2

S y = v t sine arc tan (v/c) = c t sine arc tan (c/c) = c t sine (π/4) = c t /√ 2
S = c t
If r = r (0)
S x = r (0) cosine arc tan (v/c) = r (0) √ [1 - sine² arc tan (v/c)]

S y = r (0) sine arc tan (v/c)

10 - Real time location in Polar Coordinates
With r = location; v = velocity; γ = acceleration
And r = r r (1) ;v = r' r(1) + r θ' θ(1) ; γ = (r" - rθ'²)r(1) + (2r'θ' + r θ")θ(1)
[λ (r) + ω (r)] t
S = r r (1) ℮



11 - Real time Velocity
[λ (r) + ω (r)] t
Let S = r ℮


[λ (r) + ω (r)] t
Then Velocity = P = d S /d t = {[(d r/ d t) + r [λ (r) + ω (r)]} ℮


[λ (r) + ω (r)] t
P = {[v + r [λ (r) + ω (r)]} ℮




12 - Real time Areal velocity
A = │r x d r/2│
Areal velocity: d A/d t = │r x (d r/2d t)│= │r x v/2│
And │S x (d S/2d t) │= │S x P/2│
[λ (r) + ω (r)] t
[λ (r) + ω (r)] t
=│ r ℮

x {[v + r [λ (r) + ω (r)]} ℮

}/2│
2
+ ω (r)] t
=│r x v/2│℮ [λ (r)

│
2
+ ω (r)] t
S x P/2 │=│r x v/2│℮ [λ (r)




13 - Real time Areal velocity in polar coordinates
2
+ ω (r)] t
│S x P/2 │=│r x v/2│℮ [λ (r)

= │[r r (1)] x [r' r (1) + r θ' θ (1)]/2│
2
+ ω (r)] t
= (r² θ'/2) [℮ [λ (r)
]

14- Real time motion Areal velocity visual effects in polar coordinates
2
+ ω (r)] t
│S x P/2 │=│r x v/2│℮ [λ (r)

---

= │[r r (1)] x [r' r (1) + r θ' θ (1)]/2│
2
+ ω (r)] t
= (r² θ'/2) [℮ [λ (r)
]
With λ (r) = 0
2 ω (r) t
│S x P/2 │= (r² θ'/2) [℮
]

15 - Real time motion Areal velocity in polar coordinates along the line of
measurement
2
+ ω (r)] t
│S x P/2 │=│r x v/2│℮ [λ (r)

= │[r r (1)] x [r' r (1) + r θ' θ (1)]/2│
2
+ ω (r)] t
= (r² θ'/2) [℮ [λ (r)
]
With λ (r) = 0
│
2
S x P/2 │= (r² θ'/2) [℮ ω (r) t]
= (r² θ'/2) [cosine 2 ω t + sine 2 ω t]
│S x P/2 │(x) = (r² θ'/2) cosine 2 ω t
= (r² θ'/2) [1 - sine² ω t]
│S x P/2 │(x) - (r² θ'/2) = - r² θ' sine² ω t

16- 400 years of wrong Astronomy of real time Areal velocity visual effects
│S x P/2 │(x) - (r² θ'/2) = - r² θ' sine² ω t
With ω T = arc tan (v/c)
│S x P/2 │(x) - (r² θ'/2) = - r² θ' sine² arc tan (v/c)
With (v/c) << 1
Then │S x P/2 │(x) - (r² θ'/2) = - r² θ' (v/c) ²

17- Real time Areal velocity visual effects for an ellipse
Then │S x P/2 │(x) - (r² θ'/2) = - r² θ' (v/c) ²
With r² θ' = 2 π a b
Then │S x P/2 │(x) - (r² θ'/2) = [- 2 π a b/T] (v/c) ²

18 - Advance of Perihelion visual effects
{│S x P/2 │(x) - (r² θ'/2)} 2/a² (1 - ε) ²} = [- 2 π a b/T] (v/c) ² [2/ a² (1 - ε) ²]
= - 4 π (b/a) (v/c) ²/ T (1 - ε) ²
= - 4 π {[√ (1 - ε²)]/ T (1 - ε) ²} (v/c) ²

19 - Advance of Perihelion visual effects in arc sec/ century.
{│S x P/2 │(x) - (r² θ'/2)} 2/a² (1 - ε) ²} = - 4 π {[√ (1 - ε²)]/ (1 - ε) ²} (v/c) ²
{(180/π) (36526) (3600)} = [-720x36526x3600/T] {[√ (1 - ε²)]/ (1 - ε) ²} (v/c) ²

20 - Advance of Perihelion visual effects of Planet mercury in arc sec/ century.
{│S x P/2 │(x) - (r² θ'/2)} 2/a² (1 - ε) ²} = - 4 π {[√ (1 - ε²)]/ (1 - ε) ²} (v/c) ²
{(180/π) (36526) (3600)} = [-720x36526x3600/T] {[√ (1 - ε²)]/ (1 - ε) ²} (v/c) ²
With ε = .206, T = 88; v = v* + v°; v* = orbital velocity = 47.9 km/sec v ° = spin speed
of observer on earth = 0.3km/sec Europe. v = v* + v° = 48.2 km/sec; v° (mercury) = 3
m/s
And W" (calculated) = [-720x36526x3600/T] {[√ (1 - ε²)]/ (1 - ε) ²} (v/c) ²

---

= [-720x36526x3600/88] (1.552) (48.2/300,000) ²
= 43.10 Arc sec /century --------------------------------------------I

21 - Advance of Perihelion visual effects of Planet Venus in arc sec/ century.
{│S x P/2 │(x) - (r² θ'/2)} 2/a² (1 - ε) ²} = - 4 π {[√ (1 - ε²)]/ (1 - ε) ²} (v/c) ²
{(180/π) (36526) (3600)} = [-720x36526x3600/T] {[√ (1 - ε²)]/ (1 - ε) ²} (v/c) ²
With ε = .206, T = 244.7; v = v* + v°; v* = orbital velocity = 35.12 km/sec v ° = spin
speed of observer on earth = 0.3km/sec Europe. And v° (Mercury) = 6.52km/sec
v = v* + v° = 41.94 km/sec
And W" (calculated) = [-720x36526x3600/T] {[√ (1 - ε²)]/ (1 - ε) ²} (v/c) ²
= [-720x36526x3600/244.7] (1.00761) (41.94/300,000) ²
= 7.6192 Arc sec /century
22 - Binary stars apsidal motion in arc sec
W" (calculated) = [-720x36526x3600/T] {[√ (1 - ε²)]/ (1 - ε) ²} (v/c) ² arc sec/ century

23 - Global Positioning Systems: ---------------------------------------------- II
U (seconds/day) = [24/360] [-720x 3600] {[√ (1 - ε²)]/ (1 - ε) ²} (v/c) ² sec/day

33 - Interplanetary telecommunications around the Sun round trip time delays
∆ Γ = [16π G M/c³] [1 +/- (v°/v*)] ²

24 - Interplanetary telecommunications around the Sun round trip time delays
Nahhas constant
Γ (0) = 16π G M/c³ = 247.597 µ s

25 - Mars telecommunications around the sun time delays Shapiro's historical
mistake
∆ Γ = [16π G M/c³] [1 + (v°/v*)] ² = 250 µ s ------------------------------ III

26 - Circular motion Advance of starting point visual effects
W" (calculated) = [-720x36526x3600/T] (v/c) ² arc sec/ century; ε = 0

27 - Pound- Rebka Gravitational confused for light aberrations: S = r Exp [ ω t]

Or λ (S) = λ (r) Exp [ ω t]
Measurements are defined at t = T; ω T = arc tan (v/c)
With sine ω T= sine arc tan (v/c); cosine arc tan ω(r) T = √ {1-[sine arc tan (v/c)] ²}
And with v << c; then ω(r) T= arc tan v/c ≈ v/c
Then sine ω T = sine arc tan v/c ≈ v/c;
And cosine ω T = cosine arc tan v/c = √ [1- sine ² arc tan (v/c)] = √ [1-(v/c) ²]
Or λ (S) = λ (r) {√ [1-(v/c) ²] + (v/c)} = Real λ (S) + Imaginary λ (S)
Projected or Real λ (S) = λ (r) √ [1-(v/c) ²] ≈ λ (r) [1 - 1/2(v/c) ²]
∆ λ = real λ (S) - λ (r)
∆ λ = λ (r) √ [1-(v/c) ²] - λ (r)
∆ λ = - λ (r) (v/c) ²]
∆ λ = - λ (r) (v/c) ² /2 Up

---

∆ λ (total)/ λ (r) = -1/2(v/c)²[up]-{1/2(v/c)²[down]} = - (v/c) ²
∆ λ / λ = - (v/c) ²
v² = 2gh; g = 9.81km²/s² gravitational acceleration; h = height; h =22.5meters
∆ υ/υ [Total] = -∆ λ / λ = + (v/c) ² = [2gh/c²]
∆ υ/υ = 4.93x10^-15 ---------------------------------------------------------------------- IV

28 - Light bending: Lord Eddington confusion with light aberrations
S = r Exp [ ω t]
From Kepler's Equation: r² θ' = 2h = 2A/T
With h = S²(r, t) θ'(r, t) = r² (θ, t) θ' (θ, t) = r² (θ, 0) Exp [2 ω t] θ' (θ, 0)

And θ' (θ, t) = θ' (θ, 0) θ'(0, t) = [h/ r² (θ, 0)] Exp [-2 ω(r) t]

Then θ '(θ, t) = [h/ r² (θ, 0)] {1 - 2sin²ω(r) t - 2 sin ω(r) t cosine ω(r) t}
Now [t θ'(θ, t)] = [2A/r² (θ' 0)] [1 - 2sin²ω(r) t] -2 [2A/r² (θ, 0)] [sin ω(r) t cosine ω(r) t]
= ∆ x + i ∆ y
∆ θ = ∆ x - [A/r² (θ, 0)] = - [A/r² (θ, 0)] [4sin²ω(r) t]; ω(r) t = arc tan v/c
∆ θ = - [A/r² (θ, 0)] [4sin² arc tan v/c]
∆ θ = - [A/r² (θ, 0)] 4 (v/c) ²
And [4sin² arc tan v/c] ≈ 1.757857113"
v² = GM/R; G = Gravitational constant; M = Sun mass; R = sun radius
∆ θ = [A/r² (θ, 0)] [1.75"]; A = area
The values depend on near by stars and the measured values fit this equation.
Russians in 1936; ∆ θ = 2.74
[A/r² (θ, 0)] = π/2
∆ θ = π/2(1.75") = 2.74" --------------------------------------------------------- V

29 - Universal Mechanics
S = m r; State = mass x distance
P = d S/ d t = d (m r)/d t = m (d r/d t) + (d m/d t) r
Velocity = v = (d r/d t); mass rate change = m' = (d m/d t)
P = m v + m' r; Momentum = change of state = change in location or change in mass
F = d P/d t = d² S/d t² = d [m (d r/d t) + (d m/d t)]/d t
= m d² r/d t² + (d m/d t) (d r/d t) + (d m/d t) (d r/d t) + (d² m/d t) ² r
F = m d² r/d t² + 2 (d m/d t) (d r/d t) + (d² m/d t) ² r
Force = Change of momentum
F = m a + 2 m ' v + m" r
Acceleration = a = d² r/d t²; mass acceleration = d² m/d t² = m"

30 - Real time two body problem
In Polar coordinates
With d² (m r)/dt² - (m r) θ'² = -GmM/r² Newton's Gravitational Equation (1)
And d (m²r²θ')/d t = 0 Central force law (2)

(2): d (m²r²θ')/d t = 0

---

Then m²r²θ' = constant
= H (0, 0)
= m² (0, 0) h (0, 0); h (0, 0) = r² (0, 0) θ'(0, 0)
= m² (0, 0) r² (0, 0) θ'(0, 0); h (θ, 0) = [r² (θ, 0)] [θ'(θ, 0)]
= [m² (θ, 0)] h (θ, 0); h (θ, 0) = [r² (θ, 0)] [θ'(θ, 0)]
= [m² (θ, 0)] [r² (θ, 0)] [θ'(θ, 0)]
= [m² (θ, t)] [r² (θ, t)] [θ' (θ, t)]
= [m²(θ, 0) m²(0,t)][ r²(θ,0)r²(0,t)][θ'(θ, t)]
= [m²(θ, 0) m²(0,t)][ r²(θ,0)r²(0,t)][θ'(θ, 0) θ' (0, t)]

With m²r²θ' = constant
Differentiate with respect to time
Then 2mm'r²θ' + 2m²rr'θ' + m²r²θ" = 0
Divide by m²r²θ'
Then 2 (m'/m) + 2(r'/r) + θ"/θ' = 0
This equation will have a solution 2 (m'/m) = 2[λ (m) + ì ω (m)]
And 2(r'/r) = 2[λ (r) + ì ω (r)]
And θ"/θ' = -2{λ (m) + λ (r) + [ω (m) + ω (r)]}

Then (m'/m) = [λ (m) + ì ω (m)]
Or d m/m d t = [λ (m) + ì ω (m)]
And dm/m = [λ (m) + ì ω (m)] d t
Then m = m (0) Exp [λ (m) + ì ω (m)] t
m = m (0) m (0, t); m (0, t) Exp [λ (m) + ì ω (m)] t
With initial spatial condition that can be taken at t = 0 anywhere then m (0) = m (θ, 0)
And m = m (θ, 0) m (0, t) = m (θ, 0) Exp [λ (m) + ì ω (m)] t; Exp = Exponential
And m (0, t) = Exp [λ (m) + ω (m)] t
Similarly we can get
Also, r = r (θ, 0) r (0, t) = r (θ, 0) Exp [λ (r) + ì ω (r)] t
With r (0, t) = Exp [λ (r) + ω (r)] t

Then θ'(θ, t) = {H(0, 0)/[m²(θ,0) r(θ,0)]}Exp{-2{[λ(m) + λ(r)]t + ì [ω(m) + ω(r)]t}} -----I
And θ'(θ, t) = θ' (θ, 0)]} Exp {-2{[λ (m) + λ (r)] t + ì [ω (m) + ω (r)] t}} --------------------I
And, θ'(θ, t) = θ' (θ, 0) θ' (0, t)
And θ' (0, t) = Exp {-2{[λ (m) + λ(r)] t + ì [ω (m) + ω(r)] t}
Also θ'(θ, 0) = H (0, 0)/ m² (θ, 0) r² (θ, 0)
And θ'(0, 0) = {H (0, 0)/ [m² (0, 0) r (0, 0)]}

With (1): d² (m r)/dt² - (m r) θ'² = -GmM/r² = -Gm³M/m²r²
And d² (m r)/dt² - (m r) θ'² = -Gm³ (θ, 0) m³ (0, t) M/ (m²r²)
Let m r =1/u
Then d (m r)/d t = -u'/u² = - (1/u²) (θ') d u/d θ = (- θ'/u²) d u/d θ = -H d u/d θ
And d² (m r)/dt² = -Hθ'd²u/dθ² = - Hu² [d²u/dθ²]

-Hu² [d²u/dθ²] - (1/u) (Hu²)² = -Gm³ (θ, 0) m³ (0, t) Mu²
[d²u/ dθ²] + u = Gm³ (θ, 0) m³ (0, t) M/ H²

---

t = 0; m³ (0, 0) = 1
u = Gm³ (θ, 0) M/ H² + A cosine θ =Gm (θ, 0) M (θ, 0)/ h² (θ, 0)

And m r = 1/u = 1/ [Gm (θ, 0) M (θ, 0)/ h (θ, 0) + A cosine θ]
= [h²/ Gm (θ, 0) M (θ, 0)]/ {1 + [Ah²/ Gm (θ, 0) M (θ, 0)] [cosine θ]}
= [h²/Gm (θ, 0) M (θ, 0)]/ (1 + ε cosine θ)

Then m (θ, 0) r (θ, 0) = [a (1-ε²)/ (1+εcosθ)] m (θ, 0)
Dividing by m (θ, 0)
Then r (θ, 0) = a (1-ε²)/ (1+εcosθ)
This is Newton's Classical Equation solution of two body problem which is the equation
of an ellipse of semi-major axis of length a and semi minor axis b = a √ (1 - ε²) and focus
length c = ε a
And m r = m (θ, t) r (θ, t) = m (θ, 0) m (0, t) r (θ, 0) r (0, t)
Then, r (θ, t) = [a (1-ε²)/ (1+εcosθ)] {Exp [λ(r) + ω (r)] t} ---------------------------------- II
This is Newton's time dependent equation that is missed for 350 years
If λ (m) ≈ 0 fixed mass and λ(r) ≈ 0 fixed orbit; then
Then r (θ, t) = r (θ, 0) r (0, t) = [a (1-ε²)/ (1+ε cosine θ)] Exp i ω (r) t
And m = m (θ, 0) Exp [i ω (m) t] = m (θ, 0) Exp ω (m) t

We Have θ'(0, 0) = h (0, 0)/r² (0, 0) = 2πab/ Ta² (1-ε) ²
= 2πa² [√ (1-ε²)]/T a² (1-ε) ²
= 2π [√ (1-ε²)]/T (1-ε) ²

Then θ'(0, t) = {2π [√ (1-ε²)]/ T (1-ε) ²} Exp {-2[ω (m) + ω (r)] t
= {2π [√ (1-ε²)]/ (1-ε) ²} {cosine 2[ω (m) + ω (r)] t - sin 2[ω (m) + ω (r)] t}

And θ'(0, t) = θ'(0, 0) {1- 2sin² [ω (m) + ω (r)] t}
- 2i θ'(0, 0) sin [ω (m) + ω (r)] t cosine [ω (m) + ω (r)] t

Then θ'(0, t) = θ'(0, 0) {1 - 2sine² [ω (m) t + ω (r) t]}
- 2 θ'(0, 0) sin [ω (m) + ω(r)] t cosine [ω (m) + ω(r)] t

∆ θ' (0, t) = Real ∆ θ' (0, t) + Imaginary ∆ θ (0, t)
Real ∆ θ (0, t) = θ'(0, 0) {1 - 2 sine² [ω (m) t ω(r) t]}

Let W (calculated) = ∆ θ' (0, t) (observed) = Real ∆ θ (0, t) - θ'(0, 0)
= -2θ'(0, 0) sine² [ω (m) t + ω(r) t]
= -2[2π [√ (1-ε²)]/T (1-ε) ²] sine² [ω (m) t + ω(r) t]

W (Cal) = -4π {[√ (1-ε²)]/T (1-ε) ²]} sine² [ω (m) t + ω(r) t]

If this apsidal motion is to be found as visual effects, then
With, v ° = spin velocity; v* = orbital velocity; v°/c = tan ω (m) T°; v*/c = tan ω (r) T*
Where T° = spin period; T* = orbital period

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And ω (m) T° = Inverse tan v°/c; ω (r) T*= Inverse tan v*/c
W (ob) = -4 π [√ (1-ε²)]/T (1-ε) ²] sine² [Inverse tan v°/c + Inverse tan v*/c] radians
Multiplication by 180/π

W (ob) = (-720/T) {[√ (1-ε²)]/ (1-ε) ²} sine² {Inverse tan [v°/c + v*/c]/ [1 - v° v*/c²]}
degrees and multiplication by 1 century = 36526 days and using T in days

W° (ob) = (-720x36526/Tdays) {[√ (1-ε²)]/ (1-ε) ²} x
sine² {Inverse tan [v°/c + v*/c]/ [1 - v° v*/c²]} degrees/100 years

Approximations I

With v° << c and v* << c, then v° v* <<< c² and [1 - v° v*/c²] ≈ 1
Then W° (ob) ≈ (-720x36526/Tdays) {[√ (1-ε²)]/ (1-ε) ²} x sine² Inverse tan [v°/c + v*/c]
degrees/100 years

Approximations II

With v° << c and v* << c, then sine Inverse tan [v°/c + v*/c] ≈ (v° + v*)/c

W° (Cal) = (-720x36526/Tdays) {[√ (1-ε²)]/ (1-ε) ²} x [(v° + v*)/c] ² degrees/100 years

In arc second per century

W" (Cal-arc sec) = (-720x36526x3600/Tdays) {[√ (1-ε²)]/ (1-ε) ²} x [(v° + v*)/c] ²

In Time seconds
W" (Cal- sec) = (-720x36526x3600/15Tdays) {[√ (1-ε²)]/ (1-ε) ²} x [(v° + v*)/c] ²

31- The 11 binary stars systems that no one ever solved or knew how to solve including
Einstein and all 100,000 Physicists all solved by this formula
W° (Cal) = (-720x36526/Tdays) {[√ (1-ε²)]/ (1-ε) ²} x [(v° + v*)/c] ² degrees/100 years
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11- GG Orion

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